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Find the equation of the plane through (1,2,3) and parallel to the plane 3x + 4y - 5z = 0. |
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Answer» Because plane passing through (1,2,3) ∴ x = 1, y = 2, z = 3 3x + 4y - 5z = 0 Again plane is parallel to the equation ∴ a = 3, b = 4 , c = -5 ∴ required plane equation a(x - x') + b(y - y') + c(z - z') = 0 3(x - 1) + 4(y - 2) - 5(z - 3) = 0 3x - 3 + 4y - 8 - 5z + 15 = 0 3x + 4y - 5z + 4 = 0 |
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