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Find the equation of the plane which is perpendicular to x-axis and that passes through the point (2,-1,3). |
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Answer» Equation of plane passing through point (2,-1,3) a(x – 2) + b(y + 1) + c(z – 3) = 0 ∵ Plane is perpendicular to T-axis. ∴ b = 0, c = 0 Hence required equation of plane a(x – 2) + 0(y + 1) + 0(z – 3) = 0 ⇒ a(x – 2) = 0 ⇒ x – 2 = 0 (∵a ≠ 0) |
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