1.

Find the equations of the tangent and the normal to the given curve at the indicated point fory = x3 - 2x+7 at (1, 6)

Answer»

m : dy/dx = 3x2 - 2

m at (1, 6) = 1

Tangent : y – b = m(x – a)

y – 6 = 1(x – 1)

x – y + 5 = 0

Normal : y - b = -1/m(x - a)

y – 6 = -1(x – 1)

x + y – 7 = 0



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