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Find the equations of the tangent and the normal to the given curve at the indicated point fory = x3 at P(1, 1) |
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Answer» m : dy/dx = 3x2 m at (1, 1) = 3 Tangent : y – b = m(x – a) y – 1 = 3(x – 1) y = 3x – 2 Normal : y - b = -1/m(x - a) y - 1 = -1/3(x - 1) x + 3y = 4 |
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