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Find the equations of the tangent and the normal to the following curves at the indicated points.(i) y = x4 − bx3 + 13x2 − 10x + 5 at (0, 5) [NCERT](ii) y = x4 − 6x3 + 13x2 − 10x + 5 at x = 1 [NCERT, CBSE 2011](iii) y = x2 at (0, 0) [NCERT](iv) y = 2x2 − 3x − 1 at (1, −2)(v) y2=x34-xat 2, -2(vi) y = x2 + 4x + 1 at x = 3 [CBSE 2004](vii) x2a2+y2b2=1 at acosθ, bsinθ(viii) x2a2-y2b2=1 at asecθ, btanθ(ix) y2 = 4ax at am2,2am(x) c2 x2+y2=x2 y2 at ccosθ, csinθ(ix) xy = c2 at ct,ct(xii) x2a2+y2b2=1 at x1, y1(xiii) x2a2-y2b2=1 at x0, y0 [NCERT](xiv) x23+y23 = 2 at (1, 1) [NCERT](xv) x2 = 4y at (2, 1)(xvi) y2 = 4x at (1, 2) [NCERT](xvii) 4x2 + 9y2 = 36 at (3cosθ, 2sinθ) [CBSE 2011](xviii) y2 = 4ax at (x1, y1) [CBSE 2012](xix) x2a2-y2b2=1 at 2a,b [CBSE 2014] |
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Answer» Find the equations of the tangent and the normal to the following curves at the indicated points. (i) y = x4 − bx3 + 13x2 − 10x + 5 at (0, 5) [NCERT] (ii) y = x4 − 6x3 + 13x2 − 10x + 5 at x = 1 [NCERT, CBSE 2011] (iii) y = x2 at (0, 0) [NCERT] (iv) y = 2x2 − 3x − 1 at (1, −2) (v) (vi) y = x2 + 4x + 1 at x = 3 [CBSE 2004] (vii) (viii) (ix) y2 = 4ax at (x) (ix) xy = c2 at (xii) (xiii) [NCERT] (xiv) = 2 at (1, 1) [NCERT] (xv) x2 = 4y at (2, 1) (xvi) y2 = 4x at (1, 2) [NCERT] (xvii) 4x2 + 9y2 = 36 at (3cosθ, 2sinθ) [CBSE 2011] (xviii) y2 = 4ax at (x1, y1) [CBSE 2012] (xix) [CBSE 2014] |
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