Find the equilibrium constant for below reaction at 298 K temperature. 2NOCI_((g)) hArr 2NO_((g)) + CI_(2(g)) [DeltaH^(@) = 18.4512 Kcal, DeltaS^(@) = 29.16 Cal]

Find the equilibrium constant for below reaction at 298 K temperature.

1.	Find the equilibrium constant for below reaction at 298 K temperature. 2NOCI_((g)) hArr 2NO_((g)) + CI_(2(g)) [DeltaH^(@) = 18.4512 Kcal, DeltaS^(@) = 29.16 Cal]
Answer» SOLUTION :`K_(p) = 6.94 xx 10^(-8)`