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Find the first six terms of the sequence given bya_{1}=a_{2}=a_{3}=1 \text { and } a_{n}=a_{n-1}+a_{n-2} \text { for } n>3 |
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Answer» a1=1 a2=1 a3=1 a4 = a3+a2 = 1 + 1 = 2a5 = a3+a4 = 2 + 1 = 3a6 = a4+a5 = 2 + 3 = 5 |
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