1.

Find the fundamental, first overtone and second overtone frequencies of an open organ pipe of length 20 cm. Speed of sound in air is 340 m s^-1.

Answer»


SOLUTION :`V=340m/s`
`I=20cmxx10^-2m`
Fundamental frequency
`=(V/21)=340/(2xx20xx10^-2)`
`=850 Hz`
We known first over tone
`((2V)/(2I))=(2xx340)/(2xx10xx10^-2) ` (for open pipe)`
`=1750Hz`
SECOND OVERTONE
`=3(V/2I)=3xx850=2500Hz`


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