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Find the fundamental, first overtone and second overtone frequencies of an open organ pipe of length 20 cm. Speed of sound in air is 340 m s^-1. |
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Answer» `I=20cmxx10^-2m` Fundamental frequency `=(V/21)=340/(2xx20xx10^-2)` `=850 Hz` We known first over tone `((2V)/(2I))=(2xx340)/(2xx10xx10^-2) ` (for open pipe)` `=1750Hz` SECOND OVERTONE `=3(V/2I)=3xx850=2500Hz` |
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