1.

Find the GCD of 3x2 – 48 and x2 – 7x + 12.

Answer»

3x2 – 48 = 3(x2 – 16) = 3(x2 – 43) = 3(x + 4)(x – 4)

x2 – 7x + 12 = x2 – 3x – 4x + 12 = x(x – 3) – 4 (x – 3) = (x – 3) (x – 4)

Therefore, GCD = x – 4



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