1.

Find the general solution of 2cos2x + 3sinx = 0.

Answer»

2cos22x + 3sinx = 0 

2(1 – sin22x) + 3sinx = 0 

2 – 2sin22x + 3sinx = 0 

2sin22x – 3sinx – 2 = 0 

2sin22x – 4sinx + sinx – 2 = 0 

2sin x(sin x – 2)+1 (sinx – 2) = 0 

(sin x – 2)(2sin x + 1) = 0 

sin x – 2 = 0 or 2 sin x + 1 = 0 

sin x = 2 or sin x = -1/2



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