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Find the general solution of 2cos2x + 3sinx = 0. |
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Answer» 2cos22x + 3sinx = 0 2(1 – sin22x) + 3sinx = 0 2 – 2sin22x + 3sinx = 0 2sin22x – 3sinx – 2 = 0 2sin22x – 4sinx + sinx – 2 = 0 2sin x(sin x – 2)+1 (sinx – 2) = 0 (sin x – 2)(2sin x + 1) = 0 sin x – 2 = 0 or 2 sin x + 1 = 0 sin x = 2 or sin x = -1/2 |
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