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    				| 1. | Find the general solution of each of the following differential equations: `e^(x) tan y dx +(1-e^(x))sec^(2)y dy =0` | 
| Answer» Correct Answer - `tany=C(1-e^(x))` `-int (-e^(x))/((1-e^(x)))dx + int (sec^(2)y)/(tan y) dy = log |C_(1)| rArr logh|tan y|-log |1-e^(x)|=log |C_(1)|.` ` therefore log |(tany)/((1-e^(x)))|=log |C_(1)| rArr (tan y)/((1-e^(x))) = pm C_(1) = C.` | |