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    				| 1. | Find the general solution of the differential equations `sec^2xtany dx+sec^2ytanx dy=0` | 
| Answer» Correct Answer - `tan y = C (1-e^(x))` `int (sec^(2)x)/(tanx) dx +int (sec^(2)y)/(tany) dy = log |C_(1)|rArr log |tanx|+log |tan y| = log |C_(1)|` `therefore log |tan x tany| = log |C_(1)| rArr |tan x tany|=|C_(1)|.` `therefore tanx tan y = pm C_(1) = C.` | |