1.

Find the general solution of the differential equations `sec^2xtany dx+sec^2ytanx dy=0`

Answer» Correct Answer - `tan y = C (1-e^(x))`
`int (sec^(2)x)/(tanx) dx +int (sec^(2)y)/(tany) dy = log |C_(1)|rArr log |tanx|+log |tan y| = log |C_(1)|`
`therefore log |tan x tany| = log |C_(1)| rArr |tan x tany|=|C_(1)|.`
`therefore tanx tan y = pm C_(1) = C.`


Discussion

No Comment Found