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Find the general solution of the differential equation \(\frac{dy}{dx}=\frac{y-3}{x-3}\) (x, y≠3).(a) x-3=0(b) y-3=0(c) y+3=0(d) x-3y=0The question was asked in an interview for internship.Asked question is from Methods of Solving First Order & First Degree Differential Equations in chapter Differential Equations of Mathematics – Class 12 |
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Answer» RIGHT option is (b) y-3=0 To explain: Given that, \(\frac{dy}{dx}=\frac{y-3}{x-3}\) Separating the variables, we GET \(\frac{dy}{y-3}=\frac{dx}{x-3}\) log(y-3)=log(x-3)+logC1 log(y-3)-log(x-3)=logC1 \(log(\frac{y-3}{x-3})\)=logC1 \(\frac{1}{C_1} \frac{y-3}{x-3}=0\) y-3=0 is the GENERAL solution for the given DIFFERENTIAL equation. |
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