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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

P(x; μ) = (e^-μ) (μ^x) / x! is the formula for _____(a) parametric distribution(b) continuous distribution(c) poisson distribution(d) extreme distributionThis question was posed to me in semester exam.My query is from Bernoulli Trials and Binomial Distribution in chapter Probability of Mathematics – Class 12

Answer»

The correct choice is (c) POISSON distribution

Easiest EXPLANATION: Poisson distribution SHOWS the number of times an event is likely to occur within a specified time. The Poisson distribution probability FORMULA is P(x; μ) = (e^-μ) (μ^x) / x!

2.

What is the formula for the Poisson distribution probability?(a) P(x; μ) = (e^-μ) (μ^x) / x!(b) P(x; μ) = (e^-x) (μ^x) / x!(c) P(x; μ) = (e^-μ) (μ) / x!(d) P(x; μ) = (e^-μ) (μ^x) / xI got this question in an interview for job.This interesting question is from Bernoulli Trials and Binomial Distribution topic in division Probability of Mathematics – Class 12

Answer»

Right answer is (a) P(x; μ) = (e^-μ) (μ^x) / x!

The explanation: POISSON distribution shows the NUMBER of TIMES an event is likely to OCCUR within a specified time. The Poisson distribution probability formula is P(x; μ) = (e^-μ) (μ^x) / x!

3.

How many outcomes can a Bernoulli trial have?(a) 3(b) 2(c) 5(d) 2^nThe question was asked at a job interview.I'm obligated to ask this question of Bernoulli Trials and Binomial Distribution topic in portion Probability of Mathematics – Class 12

Answer»

Right choice is (b) 2

Easiest EXPLANATION: Bernoulli trial has only two possible outcomes and is mutually EXCLUSIVE. Those two outcomes are ‘success’ and ‘failure’. So, it is also CALLED as a ‘yes’ or ‘no’ QUESTION.

4.

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be green if the first ball drawn is red? The balls are replaced in the bag.(a) \(\frac {3}{9}\)(b) \(\frac {4}{27}\)(c) \(\frac {4}{3}\)(d) \(\frac {4}{17}\)The question was asked in semester exam.The doubt is from Probability in chapter Probability of Mathematics – Class 12

Answer»

Right option is (B) \(\FRAC {4}{27}\)

The best explanation: Total number of balls = 9

The probability of the first ball to be red = \(\frac {3}{9}\)

The probability of the second ball to be green with REPLACEMENT = \(\frac {4}{9}\)

Total probability = \(\frac {3}{9} \times \frac {4}{9} = \frac {4}{27}\)

5.

A dice is thrown, what is the probability of getting an odd number?(a) 1/8(b) 1/6(c) 1/2(d) 1/4I got this question in examination.My query is from Random Variables and its Probability Distributions in chapter Probability of Mathematics – Class 12

Answer»

Correct choice is (C) 1/2

To EXPLAIN I would say: Possible outcomes when a DICE is thrown = {1,2,3,4,5,6}\(\frac {number \, of \, odd \, NUMBERS}{number \, of \, possible \, outcomes} = \frac {3}{6}=\frac {1}{2}\)

6.

A box contains a pair of socks in colours blue, red, yellow, green and pink. You reach into the box and choose a pair of socks without looking. You replace this pair and then choose another pair of socks. What is the probability that you will choose the yellow pair of socks both times?(a) \(\frac {8}{11}\)(b) \(\frac {1}{25}\)(c) \(\frac {4}{11}\)(d) \(\frac {7}{4}\)I had been asked this question in class test.The doubt is from Probability topic in section Probability of Mathematics – Class 12

Answer»

Correct answer is (b) \(\frac {1}{25}\)

Easiest explanation: PROBABILITY of YELLOW = \(\frac {1}{5}\)

Probability of choosing PINK pair of gloves twice = \(\frac {1}{5} \TIMES \frac {1}{5} = \frac {1}{25}\)

7.

Which of this represents the multiplication theorem of probability?(a) P(A∩B) = P(B) P(B/A)(b) P(A∩B) = P(A) P(B/B)(c) P(A∩B) = P(A) P(A/A)(d) P(A∩B) = P(B) P(A/B)I had been asked this question in my homework.Asked question is from Multiplication Theorem on Probability in division Probability of Mathematics – Class 12

Answer»

The correct ANSWER is (d) P(A∩B) = P(B) P(A/B)

To ELABORATE: The multiplication theorem of PROBABILITY is If A and B are two events of a random experiment with P(A) > 0 and P(B) > 0, then P(A∩B) = P(A) P(B/A) or P(A∩B) = P(B) P(A/B).

8.

Find which of the following is a Continuous random variable?(a) Number of kids in a family(b) Number of planets around the sun(c) Number of tails tossing a coin four times(d) Life of an electric fanThis question was addressed to me by my college professor while I was bunking the class.I want to ask this question from Random Variables and its Probability Distributions topic in portion Probability of Mathematics – Class 12

Answer» CORRECT option is (d) Life of an electric FAN

Explanation: EXCEPT life of an electric fan, remaining all takes finite values. Life of an electric fan takes INFINITE values so it is a CONTINUOUS random variable.
9.

Bag 1 contains 3 red and 5 black balls while another Bag 2 contains 4 red and 6 black balls. One ball is drawn at random from one of the bags and it is found to be red. Find the probability that it is drawn from bag 2.(a) 31/62(b) 16/62(c) 16/31(d) 31/32I had been asked this question in exam.This interesting question is from Bayes Theorem topic in division Probability of Mathematics – Class 12

Answer»

Correct OPTION is (c) 16/31

The explanation is: Let E1 = EVENT of choosing the bag 1, E2 = event of choosing the bag 2.

Let A be event of DRAWING a red BALL.

P(E1) = P(E2) = 1/2.

Also, P(A|E1) = P(drawing a red ball from Bag 1) = 3/8.

And P(A|E2) = P(drawing a red ball from Bag 2) = 4/10.

The probability of drawing a ball from bag 2, being GIVEN that it is red is P(E2|A).

By using Bayes’ theorem,

P(E2|A) = P(E2)P(A|E2)/( P(E1)P(A│E1)+P(E2)P(A|E2))

= (1/2 × 4/10) / ((1/2 × 3/8)) + (1/2 × 4/10)) = 16/31.

10.

P [X = x] = ^nCxp^xq^n-x is the formula for _____(a) parametric distribution(b) binomial distribution(c) poisson distribution(d) extreme distributionThe question was posed to me in an international level competition.My question comes from Bernoulli Trials and Binomial Distribution topic in portion Probability of Mathematics – Class 12

Answer»

The correct option is (b) binomial DISTRIBUTION

To explain I would say: Formula for binomial distribution is P [X = x] = ^nCxp^x q^N-x

Where n is the number of TRIALS, x is the number of successes and (n-x) is failures.

11.

Events P and Q are independent if P(A∩B) = P(A) P(B).(a) False(b) TrueI got this question in quiz.The question is from Probability topic in section Probability of Mathematics – Class 12

Answer» CORRECT answer is (B) True

The best I can explain: ACCORDING to the DEFINITION of independent events,

P(A/B) = P(A)

P(A ∩ B) ⁄ P(B) = P(A) or P(A ∩ B) = P(A) P(B). Here, P(B) ≠ 0.
12.

What is the probability of a coin landing on the tail and the dice showing 2 when a coin is tossed and dice is thrown?(a) \(\frac {1}{12}\)(b) \(\frac {8}{10}\)(c) \(\frac {7}{1}\)(d) \(\frac {4}{11}\)I have been asked this question in an internship interview.The query is from Probability topic in section Probability of Mathematics – Class 12

Answer»

The CORRECT answer is (a) \(\FRAC {1}{12}\)

Best explanation: The probability of coin LANDING on the tail = \(\frac {1}{2}\)

The probability of the dice showing 2 = \(\frac {1}{6}\)

TOTAL probability = \(\frac {1}{2} \TIMES \frac {1}{6} = \frac {1}{12}\)

13.

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be green if the first ball drawn is red? The balls are not replaced in the bag.(a) 0.82(b) 0.91(c) 1.23(d) 0.5I got this question in unit test.My enquiry is from Multiplication Theorem on Probability topic in division Probability of Mathematics – Class 12

Answer»

Correct answer is (d) 0.5

To explain I would say: Total number of balls = 9

The PROBABILITY of the FIRST ball to be red = \(\frac {3}{9}\)

The probability of the second ball to be green WITHOUT REPLACEMENT = \(\frac {4}{8} = \frac {1}{2}\) = 0.5

14.

If P(A) = 1/5, P(B) = 0, then what will be the value of P(A|B)?(a) 0(b) 1(c) Not defined(d) 1/5I got this question in exam.I want to ask this question from Conditional Probability in section Probability of Mathematics – Class 12

Answer»

Right answer is (c) Not defined

The BEST I can explain: We KNOW that P(A|B) = P(A∩B) / P(B). (By formula for conditional probability)

The value of P(B) = 0 in the GIVEN question. As the value of denominator BECOMES 0, the value of P(A|B) becomes un-defined.

15.

What is the probability of picking an ace from a pack of cards?(a) 1/8(b) 1/6(c) 1/2(d) 1/13I had been asked this question during an interview for a job.The doubt is from Random Variables and its Probability Distributions topic in chapter Probability of Mathematics – Class 12

Answer» CORRECT choice is (d) 1/13

The EXPLANATION is: TOTAL number cards in a PACK = 52

Total number of aces in a pack of cards = 4

Total probability = \(\frac {number \, of \, aces}{number \, of \, cards \, in \, a \, pack}= \frac {4}{52}=\frac {1}{13}\)
16.

A dice is thrown, what is the probability of getting an even number?(a) 1/8(b) 1/6(c) 1/2(d) 1/4This question was posed to me in a national level competition.The question is from Random Variables and its Probability Distributions topic in portion Probability of Mathematics – Class 12

Answer»

The correct option is (c) 1/2

Best EXPLANATION: Possible OUTCOMES when a dice is thrown = {1, 2, 3, 4, 5, 6}

\(\FRAC {number \, of \, even \, numbers}{number \, of \, possible \, outcomes} = \frac {3}{6}=\frac {1}{2}\)

17.

A card is chosen at random from a deck of cards and then replaced, a second card is chosen. What is the probability of choosing a four and then a queen?(a) \(\frac {7}{11}\)(b) \(\frac {7}{100}\)(c) \(\frac {1}{169}\)(d) \(\frac {9}{11}\)I have been asked this question in an online quiz.I'm obligated to ask this question of Probability in chapter Probability of Mathematics – Class 12

Answer»

Correct answer is (c) \(\frac {1}{169}\)

To ELABORATE: The probability of drawing a FOUR = \(\frac {4}{52}\)

The probability of drawing a queen = \(\frac {4}{52}\)

Total probability = \(\frac {4}{52} \TIMES \frac {4}{52} = \frac {1}{169} \)

18.

Determine the value of k?(a) 1/8(b) 1/4(c) 1/6(d) 1/2I had been asked this question in an interview for internship.I'm obligated to ask this question of Random Variables and its Probability Distributions in chapter Probability of Mathematics – Class 12

Answer»

Correct option is (a) 1/8

Best explanation: We KNOW that ∑P(xi)=1

P(X) = P(X=0) + P(X=1) + P(X=2) + P(X=3)

1 = 0 + 1/2 + 2k + 2k

1/2 = 4k

k = 1/8

19.

What are independent events?(a) If the outcome of one event does not affect the outcome of another(b) If the outcome of one event affects the outcome of another(c) Any one of the outcomes of one event does not affect the outcome of another(d) Any one of the outcomes of one event does affect the outcome of anotherThis question was posed to me by my college director while I was bunking the class.The origin of the question is Probability topic in chapter Probability of Mathematics – Class 12

Answer»

The correct answer is (a) If the OUTCOME of one event does not affect the outcome of another

Explanation: INDEPENDENT events refer to the outcome of one event does not affect the outcome of another. For example, if two PERSONS participating in two different RACES, WINNING one person doesn’t affect the winning of another person.

20.

A bag contains 4 red and 7 blue balls. What is the probability of drawing a blue ball if the first ball drawn is red? The balls drawn are replaced into the bag.(a) \(\frac {8}{11}\)(b) \(\frac {7}{11}\)(c) \(\frac {4}{11}\)(d) \(\frac {7}{4}\)I got this question in a job interview.I'd like to ask this question from Multiplication Theorem on Probability in portion Probability of Mathematics – Class 12

Answer» CORRECT answer is (B) \(\frac {7}{11}\)

The explanation is: Total number of balls = 4 + 7 = 11

The probability of the first BALL to be red = \(\frac {4}{11}\)

The probability of DRAWING blue ball as the second ball out with replacement = \(\frac {7}{11}\)
21.

A month has atmost 31days, X = Number of days in a month, is X a discrete random variable?(a) True(b) FalseThe question was posed to me in an online quiz.My question comes from Random Variables and its Probability Distributions in division Probability of Mathematics – Class 12

Answer»

Right choice is (a) True

To ELABORATE: X = Number of days in a month.

The number of days in a month can be 29,30,31

X TAKES finite values so, therefore it is Discrete and RANGE X = {28,29,30,31}

22.

A box contains 3 red and 4 blue marbles. Two marbles are drawn without replacement. What is the probability that the second marble is red if it is known the first marblel is red?(a) \(\frac {3}{7}\)(b) \(\frac {4}{7}\)(c) \(\frac {1}{3}\)(d) \(\frac {1}{7}\)I got this question in a national level competition.My doubt is from Multiplication Theorem on Probability topic in division Probability of Mathematics – Class 12

Answer»

Correct ANSWER is (c) \(\frac {1}{3}\)

For explanation: Total number of MARBLES = 7

Probability of the first MARBLE to be red = \(\frac {3}{7}\)

Probability of the SECOND marble to be red without replacement = \(\frac {2}{6} = \frac {1}{3}\)

23.

A bag contains 4 red, 2 green and 7 blue balls. What is the probability of drawing a red ball and the first ball drawn is blue? The balls drawn are replaced in the bag.(a) \(\frac {28}{169}\)(b) \(\frac {8}{11}\)(c) \(\frac {4}{128}\)(d) \(\frac {14}{11}\)The question was asked in final exam.The question is from Probability topic in section Probability of Mathematics – Class 12

Answer» RIGHT OPTION is (a) \(\frac {28}{169}\)

Easiest explanation: Total number of BALLS = 4 + 2 + 7 = 13

The probability of the first BALL to be blue = \(\frac {7}{13}\)

The probability of drawing red ball as the second ball = \(\frac {4}{13}\)

Total probability = \(\frac {7}{13} \TIMES \frac {4}{13} = \frac {28}{169}\)
24.

Find the value of P(X ≥ 1)(a) 5/7(b) 7/8(c) 3/8(d) 8/9This question was addressed to me by my school teacher while I was bunking the class.I need to ask this question from Random Variables and its Probability Distributions in chapter Probability of Mathematics – Class 12

Answer» CORRECT OPTION is (b) 7/8

Easy EXPLANATION: P(X1) = P(X=1) + P(X=2) + P(X=3)

= 1/2 + 1/8 + 1/4

= 7/8
25.

Formula for Bayes theorem is ________(a) P(A|B) = \(\frac{P(B│A)P(A)}{P(B)}\)(b) P(A|B) = \(\frac{P(A)}{P(B)}\)(c) P(A|B) = \(\frac{P(B│A)}{P(B)}\)(d) P(A|B) = \(\frac{1}{P(B)}\)The question was posed to me in an online quiz.Query is from Bayes Theorem in portion Probability of Mathematics – Class 12

Answer» CORRECT answer is (a) P(A|B) = \(\frac{P(B│A)P(A)}{P(B)}\)

For explanation: Bayes theorem FORMULA is P(A|B) = \(\frac{P(B│A)P(A)}{P(B)}\)

The formula provides relationship between P(A|B) and P(B|A). It is mainly derived from conditional PROBABILITY formula P(A|B) and P(B|A). Where,

P(A|B) = \(\frac{P(A∩B)}{P(B)}\).

P(B|A) = \(\frac{P(B∩A)}{P(A)}\).
26.

Method in which the previously calculated probabilities are revised with values of new probability is called __________(a) Revision theorem(b) Bayes theorem(c) Dependent theorem(d) Updation theoremThis question was posed to me in final exam.Enquiry is from Bayes Theorem in section Probability of Mathematics – Class 12

Answer»

The correct answer is (b) BAYES theorem

Explanation: Bayes theorem is the method in which the CALCULATED probabilities are revised with VALUES of new probabilities, whereas Updation theorem, REVISION theorem and Dependent theorem are not RELATED to the concept of probability.

27.

A dice is thrown, what is the probability of getting multiples of 3?(a) 1/8(b) 1/6(c) 1/2(d) 1/3The question was asked in an international level competition.Enquiry is from Random Variables and its Probability Distributions topic in portion Probability of Mathematics – Class 12

Answer»

Correct choice is (d) 1/3

For explanation: POSSIBLE outcomes when a dice is thrown = {1, 2, 3, 4, 5, 6}

Multiples of 3 = {3, 6}

Total PROBABILITY = \(\frac {number \, of \, multiples \, of \, 3}{number \, of \, possible \, outcomes} = \frac {2}{6}=\frac {1}{3}\)

28.

Determine the value of K?(a) 1/5(b) 2/5(c) 1/6(d) 1/2This question was addressed to me during an online exam.This question is from Random Variables and its Probability Distributions in division Probability of Mathematics – Class 12

Answer»

Right ANSWER is (c) 1/6

Explanation: We KNOW that ∑P(XI)=1

 P(X) = P(X=0) + P(X=1) + P(X=2) + P(X=3)

1 = 0 + k + 2k + 3k

1 = 6k

K = 1/6

29.

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be yellow if the first ball drawn is red? The balls are not replaced in the bag.(a) \(\frac {1}{3}\)(b) \(\frac {1}{2}\)(c) 1(d) 0This question was addressed to me in my homework.My doubt stems from Multiplication Theorem on Probability in chapter Probability of Mathematics – Class 12

Answer»

The correct CHOICE is (d) 0

The EXPLANATION: Yellow COLOR ball is not listed in the question. The bag contains only RED, white and green color BALLS. So, the probability to draw a yellow color ball out of the bag is zero.

30.

Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E∩F) = 0.2, then P(E|F) ?(a) 2/3(b) 1/3(c) 3/4(d) 1/4This question was posed to me in an interview for job.Question is taken from Conditional Probability topic in division Probability of Mathematics – Class 12

Answer»

The CORRECT option is (a) 2/3

The explanation is: We know that P(E|F) = P(E∩F) / P(F). (By FORMULA for conditional PROBABILITY)

VALUE of P(E∩F) is given to be 0.2 and value of P(F) is given to be 0.3.

P(E|F) = (0.2) / (0.3).

P(E|F) = 2 / 3.

31.

What is the probability of picking a card of the club from a pack of cards?(a) 1/8(b) 1/4(c) 1/2(d) 1/13I got this question during a job interview.Question is from Random Variables and its Probability Distributions in chapter Probability of Mathematics – Class 12

Answer»

Right option is (b) 1/4

For EXPLANATION: TOTAL number cards in a pack = 52

Total number of clubs in a pack of cards = 4

Total PROBABILITY = \(\frac {number \, of \, clubs}{number \, of \, cards \, in \, a \, pack} = \frac {13}{52}\)

32.

Find the value of P(X=3) if X is the discrete random variable taking values x1, x2, x3 where P(X=0)=0, P(X=1) = 1/4 and P(X=2) = 1/4(a) 1(b) 1/2(c) 1/3(d) 1/4I have been asked this question by my college director while I was bunking the class.The question is from Random Variables and its Probability Distributions topic in portion Probability of Mathematics – Class 12

Answer»

Right choice is (b) 1/2

To explain I would SAY: We know that ∑P(XI) = 1

P(X) = P(X=0) + P(X=1) + P(X=2) + P(X=3)

1 = 1/4 + 1/4 + P(X=3)

P(X=3) = \(\frac {1}{2}\)

33.

Bag 1 contains 4 white and 6 black balls while another Bag 2 contains 4 white and 3 black balls. One ball is drawn at random from one of the bags and it is found to be black. Find the probability that it was drawn from Bag 1.(a) 12/13(b) 5/12(c) 7/11(d) 7/12The question was posed to me in an interview for internship.My question comes from Bayes Theorem topic in division Probability of Mathematics – Class 12

Answer»

The CORRECT answer is (d) 7/12

The EXPLANATION: Let E1 = event of choosing the bag 1, E2 = event of choosing the bag 2.

Let A be event of DRAWING a black ball.

P(E1) = P(E2) = 1/2.

Also, P(A|E1) = P(drawing a black ball from Bag 1) = 6/10 = 3/5.

P(A|E2) = P(drawing a black ball from Bag 2) = 3/7.

By using BAYES’ theorem, the probability of drawing a black ball from bag 1 out of two bags is-:

P(E1|A) = P(E1)P(A|E1)/( P(E1)P(A│E1)+P(E2)P(A|E2))

= (1/2 × 3/5) / ((1/2 × 3/7)) + (1/2 × 3/5)) = 7/12.

34.

What is the formula for independent events?(a) P(AB) = P(A) P(B)(b) P(A∩B) = P(A) P(B)(c) P(A+B) = P(A) P(B)(d) P(A-B) = P(A) P(B)The question was posed to me during an online interview.My question is from Probability topic in section Probability of Mathematics – Class 12

Answer»

The correct option is (B) P(A∩B) = P(A) P(B)

The EXPLANATION: Independent events refer to the OUTCOME of one EVENT does not affect the outcome of another. The FORMULA for independent events are P(A∩B) = P(A) P(B).

35.

What is the other name for Bernoulli trials?(a) Two-way experiment(b) Dichotomous experiment(c) Nucleo experiment(d) Three-way experimentThis question was addressed to me by my college professor while I was bunking the class.The query is from Bernoulli Trials and Binomial Distribution topic in division Probability of Mathematics – Class 12

Answer»

Right answer is (b) Dichotomous EXPERIMENT

Easy EXPLANATION: Bernoulli trials is ALSO CALLED a Dichotomous experiment and is repeated n TIMES. If in each trial the probability of success is constant, then such trials are called Bernoulli trails.

36.

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white if the first ball drawn is white? The balls are replaced in the bag.(a) \(\frac {1}{9}\)(b) \(\frac {2}{9}\)(c) \(\frac {1}{8}\)(d) \(\frac {2}{8}\)The question was posed to me during an internship interview.The doubt is from Multiplication Theorem on Probability topic in portion Probability of Mathematics – Class 12

Answer»

The correct choice is (c) \(\frac {1}{8}\)

Easiest explanation: Total number of balls = 9

The probability of the FIRST BALL to be white = \(\frac {2}{9}\)

The probability of DRAWING white ball again for the second TIME without replacement = \(\frac {1}{8}\)

37.

A box contains 5 brown and 7 black pebbles. What is the probability of drawing a brown pebble if the first pebble drawn is black? The balls drawn are not replaced in the box.(a) \(\frac {5}{11}\)(b) \(\frac {8}{11}\)(c) \(\frac {4}{18}\)(d) \(\frac {14}{11}\)I have been asked this question in class test.I want to ask this question from Multiplication Theorem on Probability in section Probability of Mathematics – Class 12

Answer»

Correct answer is (a) \(\FRAC {5}{11}\)

Explanation: Total number of balls = 5 + 7 = 12

The probability of the first ball to be blue = \(\frac {7}{12}\)

The probability of drawing red ball as the second ball out without replacement = \(\frac {5}{11}\)

38.

If E and F are two events associated with the same sample space of a random experiment then P (E|F) is given by _________(a) P(E∩F) / P(F), provided P(F) ≠ 0(b) P(E∩F) / P(F), provided P(F) = 0(c) P(E∩F) / P(F)(d) P(E∩F) / P(E)I got this question during an internship interview.This key question is from Conditional Probability in chapter Probability of Mathematics – Class 12

Answer» RIGHT choice is (a) P(E∩F) / P(F), provided P(F) ≠ 0

To elaborate: E and F are two events associated with the same SAMPLE SPACE of a random experiment.

The value of P (E|F) = (E∩F) / P(F), provided P(F) ≠ 0. We know that if P(F) = 0, then the value of P(E|F) will reach a value which is not defined HENCE it is WRONG option. Also, P(E∩F) / P(F) and P(E∩F) / P(E) are wrong and do not equate to P(E|F).
39.

Given that E and F are events such that P(E) = 0.5, P(F) = 0.4 and P(E∩F) = 0.3, then what will be the value of P(F|E)?(a) 2/5(b) 3/5(c) 3/4(d) 2/4This question was posed to me during an online exam.I want to ask this question from Conditional Probability in chapter Probability of Mathematics – Class 12

Answer»

The correct CHOICE is (b) 3/5

The explanation is: We know that P(F|E) = P(E∩F) / P(E). (By FORMULA for CONDITIONAL probability)

Value of P(E∩F) is given to be 0.3 and value of P(E) is given to be 0.5.

P(F|E) = (0.3) / (0.5).

P(F|E) = 3 / 5.

40.

Find the value of F(1)(a) 1/5(b) 8/5(c) 2/5(d) 5/8I got this question at a job interview.This interesting question is from Random Variables and its Probability Distributions in section Probability of Mathematics – Class 12

Answer»

The correct CHOICE is (d) 5/8

Best explanation: F(1)=P(X ≤ 1)

P(X ≤ 1) = P(X=1) + P(X=0)

=1/2+ 1/8

= 5/8

41.

Formula for conditional probability P(A|B) is _______(a) P(A|B) = \(\frac{P(A∩B)}{P(B)}\)(b) P(A|B) = \(\frac{P(A∩B)}{P(A)}\)(c) P(A|B) = \(\frac{P(A)}{P(B)}\)(d) P(A|B) = \(\frac{P(B)}{P(A)}\)This question was posed to me in quiz.My question is based upon Bayes Theorem in chapter Probability of Mathematics – Class 12

Answer»

Correct CHOICE is (a) P(A|B) = \(\frac{P(A∩B)}{P(B)}\)

For explanation I WOULD say: Conditional probability P(A | B) INDICATES the probability of event ‘A’ happening given that event B has happened.

Which in formula can be written as P(A|B) = \(\frac{P(A∩B)}{P(B)}\).

Whereas formula’s P(A|B) = \(\frac{P(A∩B)}{P(A)}\), P(A|B) = \(\frac{P(A)}{P(B)}\), P(A|B) = \(\frac{P(B)}{P(A)}\) doesn’t satisfies the specified conditions.

42.

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white if the first ball drawn is white? The balls are not replaced in the bag.(a) \(\frac {1}{9}\)(b) \(\frac {2}{9}\)(c) \(\frac {7}{8}\)(d) \(\frac {1}{8}\)The question was asked by my school teacher while I was bunking the class.My question is based upon Multiplication Theorem on Probability topic in section Probability of Mathematics – Class 12

Answer»

Correct answer is (d) \(\frac {1}{8}\)

To elaborate: Total number of balls = 9

The PROBABILITY of the FIRST ball to be white = \(\frac {2}{9}\)

The probability of DRAWING white ball again for the second time without replacement = \(\frac {1}{8}\)

43.

If P(A) = 5/13, P(B) = 7/13 and P(A∩B) = 3/13, evaluate P(A|B).(a) 1/7(b) 3/7(c) 3/5(d) 2/7The question was posed to me at a job interview.I need to ask this question from Conditional Probability in division Probability of Mathematics – Class 12

Answer»

Correct ANSWER is (b) 3/7

To explain: We know that P(A|B) = P(A∩B) / P(B). (By FORMULA for CONDITIONAL probability)

Which is equivalent to (3/13) / (7/13), HENCE the value of P(A|B) = 3/7.

44.

The Poisson distribution shows the number of times an event is likely to occur in a particular time interval.(a) False(b) TrueThe question was asked in an international level competition.My question is from Bernoulli Trials and Binomial Distribution topic in section Probability of Mathematics – Class 12

Answer»

Correct option is (B) True

To elaborate: Poisson distribution is used for INDEPENDENT events and it shows the number of times an EVENT is going to occur in SPECIFIED intervals of time. The FORMULA for Poisson distribution is P(x; μ) = (e^-μ) (μ^x) / x!

45.

Bernoulli trials only deal with mutually exclusive outcomes.(a) True(b) FalseThe question was posed to me by my school teacher while I was bunking the class.This key question is from Bernoulli Trials and Binomial Distribution in chapter Probability of Mathematics – Class 12

Answer»

Right answer is (a) True

Easiest EXPLANATION: A RANDOM experiment that has only two mutually exclusive outcomes called ‘success’ and ‘FAILURE’. This experiment is called a Dichotomous experiment and is repeated N times. So, it is called as BERNOULLI trials.

46.

Find the value of F(4)(a) 9/11(b) 1(c) 5/11(d) 1/2I got this question in my homework.I need to ask this question from Random Variables and its Probability Distributions in division Probability of Mathematics – Class 12

Answer»

The CORRECT CHOICE is (b) 1

The best I can explain: F(4)=P(X ≤ 4)

P(X ≤ 4) = P(X=4) + P(X=3) + P (X=2) + P(X=1) + P(X=0)

= 1/11 + 4/11 + 2/11 + 3/11 + 1/11

= 1

47.

A man is known to speak truth 3 out of 4 times. He throws a die and reports that it is a six. Find the probability that it is actually a six.(a) 1/8(b) 5/8(c) 2/7(d) 3/8I have been asked this question in homework.My query is from Bayes Theorem topic in chapter Probability of Mathematics – Class 12

Answer»

Correct ANSWER is (d) 3/8

Easiest explanation: Let E = EVENT that the man reports that six in the throwing of the die and let, S1 = event that six occurs and S2 = event that six does not occur.

P(S1) = Probability that six occurs = 1/6.

P(S2) = Probability that six does not occur = 5/6.

Also, P(E|S1) = P(Probability that man reports six occurs when six actually has occurred on the die) = 3/4.

P(E|S2) = P(Probability that man reports six occurs when six not actually occurred on the die) =

1 – 3/4 = 1/4.

By using Bayes’ theorem,

P(S2|E) = P(S1)P(E|S1)/(P(S1)P(E│S1)+P(S2)P(E|S2))

= (1/6 × 3/4) / ((1/6 × 3/4)) + (5/6 × 1/4)) = 3/8.

48.

A bag contains 6 pink and 8 white pebbles. What is the probability of drawing a brown pebble if the first pebble drawn is pink? The balls drawn are not replaced in the bag.(a) 0(b) \(\frac {8}{11}\)(c) 1(d) \(\frac {14}{11}\)I got this question during an online interview.My question is taken from Multiplication Theorem on Probability in section Probability of Mathematics – Class 12

Answer» RIGHT answer is (a) 0

The BEST explanation: The TOTAL probability is zero because the BAG contains only PINK and white coloured pebbles. There are no brown coloured pebbles in the bag.
49.

What is the formula for binomial distribution?(a) P [X = x] = ^nCn p^x q^n-x(b) P [X = x] = ^xCx p^x q^n-x(c) P [X = x] = ^nCx p^x q^n-x(d) P [X = x] = ^nCx p^n q^n-xThis question was posed to me in a job interview.The origin of the question is Bernoulli Trials and Binomial Distribution topic in portion Probability of Mathematics – Class 12

Answer»

The CORRECT choice is (C) P [X = x] = ^NCX p^x q^N-x

For explanation I would say: Formula for binomial DISTRIBUTION is P [X = x] = ^nCxp^x q^n-x

Where n is the number of trials, x is the number of successes and (n-x) is failures.

50.

The Poisson distribution comes under which probability distribution?(a) Continuous probability distribution(b) Sine probability distribution(c) Discrete probability distribution(d) Mutual probability distributionThis question was addressed to me in an online interview.This interesting question is from Bernoulli Trials and Binomial Distribution in portion Probability of Mathematics – Class 12

Answer»

Right choice is (c) Discrete probability distribution

Best explanation: Poisson distribution shows the number of times an EVENT is LIKELY to OCCUR within a specified time. It is USED only for independent EVENTS that occur at a constant rate within a given interval of time.