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A box contains 3 red and 4 blue marbles. Two marbles are drawn without replacement. What is the probability that the second marble is red if it is known the first marblel is red?(a) \(\frac {3}{7}\)(b) \(\frac {4}{7}\)(c) \(\frac {1}{3}\)(d) \(\frac {1}{7}\)I got this question in a national level competition.My doubt is from Multiplication Theorem on Probability topic in division Probability of Mathematics – Class 12 |
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Answer» Correct ANSWER is (c) \(\frac {1}{3}\) |
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