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A box contains 3 red and 4 blue marbles. Two marbles are drawn without replacement. What is the probability that the second marble is red if it is known the first marblel is red?(a) \(\frac {3}{7}\)(b) \(\frac {4}{7}\)(c) \(\frac {1}{3}\)(d) \(\frac {1}{7}\)I got this question in a national level competition.My doubt is from Multiplication Theorem on Probability topic in division Probability of Mathematics – Class 12

Answer»

Correct ANSWER is (c) \(\frac {1}{3}\)

For explanation: Total number of MARBLES = 7

Probability of the first MARBLE to be red = \(\frac {3}{7}\)

Probability of the SECOND marble to be red without replacement = \(\frac {2}{6} = \frac {1}{3}\)



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