1.

Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E∩F) = 0.2, then P(E|F) ?(a) 2/3(b) 1/3(c) 3/4(d) 1/4This question was posed to me in an interview for job.Question is taken from Conditional Probability topic in division Probability of Mathematics – Class 12

Answer»

The CORRECT option is (a) 2/3

The explanation is: We know that P(E|F) = P(E∩F) / P(F). (By FORMULA for conditional PROBABILITY)

VALUE of P(E∩F) is given to be 0.2 and value of P(F) is given to be 0.3.

P(E|F) = (0.2) / (0.3).

P(E|F) = 2 / 3.



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