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A bag contains 4 red and 7 blue balls. What is the probability of drawing a blue ball if the first ball drawn is red? The balls drawn are replaced into the bag.(a) \(\frac {8}{11}\)(b) \(\frac {7}{11}\)(c) \(\frac {4}{11}\)(d) \(\frac {7}{4}\)I got this question in a job interview.I'd like to ask this question from Multiplication Theorem on Probability in portion Probability of Mathematics – Class 12

Answer» CORRECT answer is (B) \(\frac {7}{11}\)

The explanation is: Total number of balls = 4 + 7 = 11

The probability of the first BALL to be red = \(\frac {4}{11}\)

The probability of DRAWING blue ball as the second ball out with replacement = \(\frac {7}{11}\)


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