1.

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white if the first ball drawn is white? The balls are not replaced in the bag.(a) \(\frac {1}{9}\)(b) \(\frac {2}{9}\)(c) \(\frac {7}{8}\)(d) \(\frac {1}{8}\)The question was asked by my school teacher while I was bunking the class.My question is based upon Multiplication Theorem on Probability topic in section Probability of Mathematics – Class 12

Answer»

Correct answer is (d) \(\frac {1}{8}\)

To elaborate: Total number of balls = 9

The PROBABILITY of the FIRST ball to be white = \(\frac {2}{9}\)

The probability of DRAWING white ball again for the second time without replacement = \(\frac {1}{8}\)



Discussion

No Comment Found

Related InterviewSolutions