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A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white if the first ball drawn is white? The balls are not replaced in the bag.(a) \(\frac {1}{9}\)(b) \(\frac {2}{9}\)(c) \(\frac {7}{8}\)(d) \(\frac {1}{8}\)The question was asked by my school teacher while I was bunking the class.My question is based upon Multiplication Theorem on Probability topic in section Probability of Mathematics – Class 12 |
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Answer» Correct answer is (d) \(\frac {1}{8}\) |
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