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A bag contains 4 red, 2 green and 7 blue balls. What is the probability of drawing a red ball and the first ball drawn is blue? The balls drawn are replaced in the bag.(a) \(\frac {28}{169}\)(b) \(\frac {8}{11}\)(c) \(\frac {4}{128}\)(d) \(\frac {14}{11}\)The question was asked in final exam.The question is from Probability topic in section Probability of Mathematics – Class 12 |
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Answer» RIGHT OPTION is (a) \(\frac {28}{169}\) Easiest explanation: Total number of BALLS = 4 + 2 + 7 = 13 The probability of the first BALL to be blue = \(\frac {7}{13}\) The probability of drawing red ball as the second ball = \(\frac {4}{13}\) Total probability = \(\frac {7}{13} \TIMES \frac {4}{13} = \frac {28}{169}\) |
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