1.

A box contains 5 brown and 7 black pebbles. What is the probability of drawing a brown pebble if the first pebble drawn is black? The balls drawn are not replaced in the box.(a) \(\frac {5}{11}\)(b) \(\frac {8}{11}\)(c) \(\frac {4}{18}\)(d) \(\frac {14}{11}\)I have been asked this question in class test.I want to ask this question from Multiplication Theorem on Probability in section Probability of Mathematics – Class 12

Answer»

Correct answer is (a) \(\FRAC {5}{11}\)

Explanation: Total number of balls = 5 + 7 = 12

The probability of the first ball to be blue = \(\frac {7}{12}\)

The probability of drawing red ball as the second ball out without replacement = \(\frac {5}{11}\)



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