Formula for conditional probability P(A|B) is _______(a) P(A|B) = \(\frac{P(A∩B)}{P(B)}\)(b) P(A|B) = \(\frac{P(A∩B)}{P(A)}\)(c) P(A|B) = \(\frac{P(A)}{P(B)}\)(d) P(A|B) = \(\frac{P(B)}{P(A)}\)This question was posed to me in quiz.My question is based upon Bayes Theorem in chapter Probability of Mathematics – Class 12

Formula for conditional probability P(A|B) is _______(a) P(A|B) = \(\f

1.	Formula for conditional probability P(A\|B) is _______(a) P(A\|B) = \(\frac{P(A∩B)}{P(B)}\)(b) P(A\|B) = \(\frac{P(A∩B)}{P(A)}\)(c) P(A\|B) = \(\frac{P(A)}{P(B)}\)(d) P(A\|B) = \(\frac{P(B)}{P(A)}\)This question was posed to me in quiz.My question is based upon Bayes Theorem in chapter Probability of Mathematics – Class 12
Answer» Correct CHOICE is (a) P(A\|B) = \(\frac{P(A∩B)}{P(B)}\) For explanation I WOULD say: Conditional probability P(A \| B) INDICATES the probability of event ‘A’ happening given that event B has happened. Which in formula can be written as P(A\|B) = \(\frac{P(A∩B)}{P(B)}\). Whereas formula’s P(A\|B) = \(\frac{P(A∩B)}{P(A)}\), P(A\|B) = \(\frac{P(A)}{P(B)}\), P(A\|B) = \(\frac{P(B)}{P(A)}\) doesn’t satisfies the specified conditions.

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