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A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be yellow if the first ball drawn is red? The balls are not replaced in the bag.(a) \(\frac {1}{3}\)(b) \(\frac {1}{2}\)(c) 1(d) 0This question was addressed to me in my homework.My doubt stems from Multiplication Theorem on Probability in chapter Probability of Mathematics – Class 12 |
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Answer» The correct CHOICE is (d) 0 |
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