1.

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white if the first ball drawn is white? The balls are replaced in the bag.(a) \(\frac {1}{9}\)(b) \(\frac {2}{9}\)(c) \(\frac {1}{8}\)(d) \(\frac {2}{8}\)The question was posed to me during an internship interview.The doubt is from Multiplication Theorem on Probability topic in portion Probability of Mathematics – Class 12

Answer»

The correct choice is (c) \(\frac {1}{8}\)

Easiest explanation: Total number of balls = 9

The probability of the FIRST BALL to be white = \(\frac {2}{9}\)

The probability of DRAWING white ball again for the second TIME without replacement = \(\frac {1}{8}\)



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