InterviewSolution
Saved Bookmarks
| 1. |
Find the greatest distance of the point `P(10 ,7)`from the circle `x^2+y^2-4x-2y-20=0`A. 10B. 15C. 5D. none of these |
|
Answer» Correct Answer - B We have, `S_(1)=10^(2)+7^(2)-4xx10-2xx7-20 gt 0`. So, P lies outside the circle. Join P with the centre C(2, 1) of the given circle. Suppose PC cuts the circle at A and B. Then, PB is the greatest distance of P from the circle. Now, we have `PC=sqrt((10-2)^(2)+(7-1)^(2))=10` and, CB = Radius = `sqrt(4+1+20)=5` `:. PB=PC+CB=(10+5)=15`. |
|