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Find the greatest number that will divide 149, 247 and 622 leaving remainders 5, 7 and 10 respectively1). 102). 123). 184). 8 |
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Answer» The greatest number that will DIVIDE 149, 247 and 622 LEAVING remainder 5, 7 and 10 Factor of (149 – 5) = 144 = 12 × 12 Factor of (247 – 7) = 240 = 12 × 20 Factor of (622 – 10) = 612 = 12 × 51 Such that 12 is the common number and greatest number. |
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