Find the greatest number that will divide 382 and 509 and 636 leaving

1.	Find the greatest number that will divide 382 and 509 and 636 leaving remainders 4 and 5 and 6 respectively.
Answer» First of all subtract 382 by 4, 509 by 5 and 636 by 6. 382-4 = 378 509-5 = 504 636-6 = 630 Then, take out the HCF of 378, 504 and 630 378 and 504 504 = 378 x 1 + 126 378 = 126 x 3 + 0 HCF (378 and 504) = 126 Now, HCF (126 and 630) = 126 The greatest number that divided these number is 126. First of all subtract 382 by 4, 509 by 5 and 636 by 6. 382 - 4 = 378 509 - 5 = 504 636 - 6 = 630 Factor of 378, 504 and 630 is 378 = 2 x 3 x 3 x 3 x 7 504 = 2 x 2 x 2 x 3 x 3 x 7 630 = 2 x 3 x 3 x 5 x 7 Common factor = 2 x 3 x 3 x 7 = 126 H.C.F. = 126 126 is the greatest number that will divide 382, 509 and 636 leaving remainders 4, 5 and 6 respectively.

Find the greatest number that will divide 382 and 509 and 636 leaving remainders 4 and 5 and 6 respectively.

Answer»

First of all subtract 382 by 4, 509 by 5 and 636 by 6.

382-4 = 378

509-5 = 504

636-6 = 630

Then, take out the HCF of 378, 504 and 630

378 and 504

504 = 378 x 1 + 126

378 = 126 x 3 + 0

HCF (378 and 504) = 126

Now, HCF (126 and 630) = 126

The greatest number that divided these number is 126.

First of all subtract 382 by 4, 509 by 5 and 636 by 6.

382 - 4 = 378

509 - 5 = 504

636 - 6 = 630

Factor of 378, 504 and 630 is

378 = 2 x 3 x 3 x 3 x 7

504 = 2 x 2 x 2 x 3 x 3 x 7

630 = 2 x 3 x 3 x 5 x 7

Common factor = 2 x 3 x 3 x 7 = 126

H.C.F. = 126

126 is the greatest number that will divide 382, 509 and 636 leaving remainders 4, 5 and 6 respectively.

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