1.

Find the H.C.F. of 252525 and 363636.

Answer»

To find the HCF of 252525 and 363636 by using

Euclid’s Division algorithm.

363636 = 252525 x 1 + 111111

The remainder 111111 ≠ 0

By division of Euclid’s algorithm

252525 = 111111 x 2 + 30303

The remainder 30303 ≠ 0

Again by division of Euclid’s algorithm

111111 = 30303 x 3 + 20202

The remainder 20202 ≠ 0

Again by division of Euclid’s algorithm.

30303 = 20202 + 10101

The remainder 10101 ≠ 0

Again by division of Euclid’s algorithm.

20202 = 10101 x 2 + 0

The remainder is 0

∴ The H.C.F. is 10101



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