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Find the HCF and LCM. i. 14, 28 ii. 32, 16iii. 17, 102, 170 |
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Answer» i. 14 = 2 x 7 28 = 2 x 14 = 2 x 2 x 7 ∴ HCF of 14 and 28 = 2 x 7 = 14 LCM of 14 and 28 = 2 x 2 x 7 = 28 ii. 32 = 2 x 16 = 2 x 2 x 8 = 2 x 2 x 2 x 4 = 2 x 2 x 2 x 2 x 2 16 = 2 x 8 = 2 x 2 x 4 = 2 x 2 x 2 x 2 ∴ HCF of 32 and 16 = 2 x 2 x 2 x 2 = 16 ∴ LCM of 32 and 16 = 2 x 2 x 2 x 2 x 2 = 32 iii. 17 = 17 x 1 102 = 2 x 51 = 2 x 3 x 17 170 = 2 x 85 = 2 x 5 x 17 ∴ HCF of 17, 102 and 170 = 17 ∴ LCM of 17, 102 and 170 = 17 x 2 x 3 x 5 = 510 |
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