Find the HCF(i)25,40 (ii) 56, 32 (iii) 40, 60, 75(v)18,32,48 (vi) 105, – InterviewSolution

1.

Find the HCF(i)25,40 (ii) 56, 32 (iii) 40, 60, 75(v)18,32,48 (vi) 105, 154 (vii) 42, 45, 48(ix) 56,57 (0777, 315, 588

Answer»

777 = 7×3×37 315 = 3×3×5×7 588 = 2×2×3×7×7 so HCF = 3×7 = 21

how to solve I don't understand

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