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Find the HCF of `18p^(2)qr , 24pq^(2)r` and `27 pqr^(2)`.A. 216 pqrB. 3pqrC. `216(pqr)^(2)`D. `3(pqr)^(2)` |
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Answer» Correct Answer - B HCF `(18p^(2)qr, 24pq^(2)r and 27 pqr^(2))` HCF `[(pqr) (18 p) , (pqr) (24q) , (pqr) (27r)`] = (pqr) HCF (18p , 24 q , 27 r) = (par)HCF [3(6p) , 3(8q) , 3(9r)] = (3pqr) HCF (6p , 8q , 9r) = 3pqr (1) = 3pqr Hence , the correct option is (b) . |
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