1.

Find the (i) lengths of axes, (ii) coordinates of the vertices, (iii) coordinates of the foci, (iv) eccentricity, and (v) length of the latus rectum of the hyperbola. Horizontal Hyperbola:For general form of Hyperbola: x2/a2 – y2/b2 = 1 ……..(1) Vertical Hyperbola:For general form of Hyperbola:y2/a2 – x2/b2 = 1 ……..(2) 24x2 – 25y2 = 600

Answer»

Divide both sides by 600

x2/25 – y2/24 = 1

Given equation is of the form x2/a2 – y2/b2 = 1

On comparing given equation with (1), we get

a = 5 and b = 2√6

Then,

c2 = a2 + b2

c2 = 25 + 24 = 49

or c = 7

Now,

(i) Lengths of the axes:

Length of Transverse axis = 2a = 10 units

Length of Conjugate axis = 2b = 4√6 units

(ii) Coordinates of the vertices: (±a, 0) = (±5, 0)

(iii) Coordinates of the foci: (±c, 0) = (±7, 0)

(iv) Eccentricity: e = c/a = 7/5

(v) Length of the latus rectum: 2b2/a = 48/5 units



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