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Find the (i) lengths of axes, (ii) coordinates of the vertices, (iii) coordinates of the foci, (iv) eccentricity, and (v) length of the latus rectum of the hyperbola. Horizontal Hyperbola:For general form of Hyperbola: x2/a2 – y2/b2 = 1 ……..(1) Vertical Hyperbola:For general form of Hyperbola:y2/a2 – x2/b2 = 1 ……..(2) 24x2 – 25y2 = 600 |
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Answer» Divide both sides by 600 x2/25 – y2/24 = 1 Given equation is of the form x2/a2 – y2/b2 = 1 On comparing given equation with (1), we get a = 5 and b = 2√6 Then, c2 = a2 + b2 c2 = 25 + 24 = 49 or c = 7 Now, (i) Lengths of the axes: Length of Transverse axis = 2a = 10 units Length of Conjugate axis = 2b = 4√6 units (ii) Coordinates of the vertices: (±a, 0) = (±5, 0) (iii) Coordinates of the foci: (±c, 0) = (±7, 0) (iv) Eccentricity: e = c/a = 7/5 (v) Length of the latus rectum: 2b2/a = 48/5 units |
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