InterviewSolution
Saved Bookmarks
| 1. |
Find the (i) lengths of axes, (ii) coordinates of the vertices, (iii) coordinates of the foci, (iv) eccentricity, and (v) length of the latus rectum of the hyperbola. Horizontal Hyperbola:For general form of Hyperbola: x2/a2 – y2/b2 = 1 ……..(1) Vertical Hyperbola:For general form of Hyperbola:y2/a2 – x2/b2 = 1 ……..(2) y2/16 – x2/49 = 1 |
|
Answer» Given equation is of the form y2/a2 – x2/b2 = 1 On comparing given equation with (2), we get a = 4 and b = 7 Then, c2 = a2 + b2 c2 = 16 + 49 = 65 or c = √65 Now, (i) Lengths of the axes: Length of Transverse axis = 2a = 8 units Length of Conjugate axis = 2b = 14 units (ii) Coordinates of the vertices: (0, ±a) = (0, ±4) (iii) Coordinates of the foci: (0, ±c) = (0, ±√65) (iv) Eccentricity: e = c/a = √65/4 (v) Length of the latus rectum: 2b2/a = 49/2 units |
|