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Find the (i) lengths of axes, (ii) coordinates of the vertices, (iii) coordinates of the foci, (iv) eccentricity, and (v) length of the latus rectum of the hyperbola. Horizontal Hyperbola:For general form of Hyperbola: x2/a2 – y2/b2 = 1 ……..(1) Vertical Hyperbola:For general form of Hyperbola:y2/a2 – x2/b2 = 1 ……..(2) 3x2 – 2y2 = 6 |
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Answer» Divide each side by 6 x2/2 – y2/3 = 1 Given equation is of the form x2/a2 – y2/b2 = 1 On comparing given equation with (1), we get a = √2 and b = √3 Then, c2 = a2 + b2 c2 = 2 + 3 = 5 or c = √5 Now, (i) Lengths of the axes: Length of Transverse axis = 2a = 2√2 units Length of Conjugate axis = 2b = 2√3 units (ii) Coordinates of the vertices: (±a, 0) = (±√2, 0) (iii) Coordinates of the foci: (±c, 0) = (±√5, 0) (iv) Eccentricity: e = c/a = √(5/2) (v) Length of the latus rectum: 2b2/a = 3√2 units |
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