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Find the interval in which the function f given f(x) = 2x2 - 3x is strictly increasing. |
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Answer» f(x) = 2x2 - 3x diff wrt x f1(x) = 4x - 3 f1 (x) = 0 ⇒ 4x - 3 = 0 or 4x = 3 ⇒ x = 3/4 ∴ Point x = 3/4 divides the real line into two disjoint intervals (- ∞, 3/4) and (3/4, ∞) In the interval (3/4, ∞), f1(x) = 4x - 3 > 0 ∴ f is strictly increasing in (3/4, ∞) |
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