1.

Find the interval in which the function f given f(x) = 2x2 - 3x is strictly increasing.

Answer»

f(x) = 2x2 - 3x

diff wrt x

f1(x) = 4x - 3

f1 (x) = 0 ⇒ 4x - 3 = 0

or 4x = 3

⇒ x = 3/4

∴ Point x = 3/4 divides the real line into two disjoint intervals (- ∞, 3/4) and (3/4, ∞) In the interval (3/4, ∞), f1(x) = 4x - 3 > 0

∴ f is strictly increasing in (3/4, ∞)



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