

InterviewSolution
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Find the inverse relation R-1 in each of the following cases:(i) R= {(1, 2), (1, 3), (2, 3), (3, 2), (5, 6)}(ii) R= {(x, y) : x, y ∈ N; x + 2y = 8}(iii) R is a relation from {11, 12, 13} to (8, 10, 12} defined by y = x – 3 |
Answer» (i) Given as R= {(1, 2), (1, 3), (2, 3), (3, 2), (5, 6)} Therefore, R‑1 = {(2, 1), (3, 1), (3, 2), (2, 3), (6, 5)} (ii) Given as R= {(x, y): x, y ∈ N; x + 2y = 8} Since, x + 2y = 8 x = 8 – 2y As y ∈ N, Putting the values of y = 1, 2, 3,…… till x ∈ N If, y = 1, x = 8 – 2(1) = 8 – 2 = 6 If, y = 2, x = 8 – 2(2) = 8 – 4 = 4 If, y = 3, x = 8 – 2(3) = 8 – 6 = 2 If, y = 4, x = 8 – 2(4) = 8 – 8 = 0 Then, y cannot hold value 4 because x = 0 for y = 4 which is not a natural number. ∴ R = {(2, 3), (4, 2), (6, 1)} R‑1 = {(3, 2), (2, 4), (1, 6)} (iii) Given as R is the relation from {11, 12, 13} to (8, 10, 12} defined by y = x – 3 Since, x = {11, 12, 13} and y = (8, 10, 12} y = x – 3 If, x = 11, y = 11 – 3 = 8 ∈ (8, 10, 12} If, x = 12, y = 12 – 3 = 9 ∉ (8, 10, 12} If, x = 13, y = 13 – 3 = 10 ∈ (8, 10, 12} ∴ R = {(11, 8), (13, 10)} Thus, R‑1 = {(8, 11), (10, 13)} |
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