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Find the kinetic energy, potential energy and total energy in first and second orbit of hydrogen atom if potential energy in first orbit is taken to be zero. |
Answer» `E_(1)= -13.60eV K_(1)=-E_(1)=13.60 eV U_(1)2E_(1)=-27.20eV` `E_(2)=(E_(1))/((2)^(2))= -3.40 eV K_(2)=3.40eV` and `U_(2)= - 6.80eV` Now, `U_(1)=0,i.e.,` potential energy has been increased by `27.20 eV` while kinetic energy will remain unchanged. So values of kinetic energy, potential energy and total energy in first orbit are `13.60 eV, 0,13.60` respectively and for second orbit these valeus are `3.40 eV, 20.40 eV` and `23.80 eV`. |
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