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Find the quantum number `n` corresponding to the excited state of `He^(+)` ion, if on transition to the ground state that ion emits two photons in succession with wave lengths `108.5` and `30.4 nm`. |
Answer» Correct Answer - `n=5` Total energy of radiation `E=(hc)/(lambda_(1))+(hc)/(lambda_(2))` `13.6xx4xx(1-(1)/n^(2))=((1240)/(108.5)+(1240)/(30.4))eV` `1-(1)/(n^(2))=(1)/(13.6xx4)xx52.22` |
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