Find The Largest Number Of 4-digits Divisible By 12, 15 And 18?

1.	Find The Largest Number Of 4-digits Divisible By 12, 15 And 18?
Answer» Required largest number must be divisible by the L.C.M. of 12, 15 and 18 L.C.M. of 12, 15 and 18 12 = 2 × 2 × 3 15 =5 × 3 18 = 2 × 3 × 3 L.C.M. = 180 Now divide 9999 by 180, we get REMAINDER as 99 The required largest number = (9999 – 99) =9900 Number 9900 is exactly divisible by 180. Required largest number must be divisible by the L.C.M. of 12, 15 and 18 L.C.M. of 12, 15 and 18 12 = 2 × 2 × 3 15 =5 × 3 18 = 2 × 3 × 3 L.C.M. = 180 Now divide 9999 by 180, we get remainder as 99 The required largest number = (9999 – 99) =9900 Number 9900 is exactly divisible by 180.

Answer»

Required largest number must be divisible by the L.C.M. of 12, 15 and 18

L.C.M. of 12, 15 and 18

12 = 2 × 2 × 3

15 =5 × 3

18 = 2 × 3 × 3

L.C.M. = 180

Now divide 9999 by 180, we get REMAINDER as 99

The required largest number = (9999 – 99) =9900

Number 9900 is exactly divisible by 180.

Required largest number must be divisible by the L.C.M. of 12, 15 and 18

L.C.M. of 12, 15 and 18

12 = 2 × 2 × 3

15 =5 × 3

18 = 2 × 3 × 3

L.C.M. = 180

Now divide 9999 by 180, we get remainder as 99

The required largest number = (9999 – 99) =9900

Number 9900 is exactly divisible by 180.

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