1.

Find the LCM of 3y +12, y2 –16 and y4–64y.

Answer»

3y + 12 = 3 (y + 4)

y2 – 16 = (y +4) (y – 4)

y4 - 64y = y(y3 - 64) - y(y - 4)(y2 + 4y + 16)

∴ LCM of given polynomials = 3y ( y – 4) ( y + 4) (y2 + 4y + 16)



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