InterviewSolution
Saved Bookmarks
| 1. |
Find the least common multiple of xy (k2 + 1) + k(x2 + y2) and xy(k2 – 1) + k (x2 – y2) |
|
Answer» xy (k2 + 1) + k(x2 + y2) = k2 xy + xy + kx2 + ky2 = (k2 xy + kx2) + (ky2 + xy) = kx(ky + x) + y (ky + x) = (ky + x) (kx + y) xy (k2 – 1) + k(x2 – y2) = k2 xy – xy + kx2 – ky2 = (k2xy + kx2) – xy – ky2 = kx(ky + x) -y (ky + x) = (ky + x) (kx – y) L.C.M. = (ky + x) (kx + y) (kx – y) = (ky + x) (k2 x2 – y2) The least common multiple is (ky + x) (k2 x2 – y2) |
|