1.

Find the least number which when divided by 12, 15, 18 and 27 leaves remainders 10, 13, 16 and 25 respectively.1). 5402). 5383). 5424). 552

Answer»

As per the given data,

LCM of 12, 15, 18 and 27 = 2 × 2 × 3 × 3 × 3 × 5 × 1 = 540

We NEED the remainders 10, 13, 16 and 25

⇒ 12 - 10 = 2, 15 - 13 = 2, 18 - 16 = 2, 27 - 25 = 2

∴ Difference is 2 in each case

⇒ We need to subtract 2 to from the LCM of 12, 15, 18, 27 = 540 - 2 = 538

∴ Least number = 538


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