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Find the least number which when divided by 12, 15, 18 and 27 leaves remainders 10, 13, 16 and 25 respectively.1). 5402). 5383). 5424). 552 |
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Answer» As per the given data, LCM of 12, 15, 18 and 27 = 2 × 2 × 3 × 3 × 3 × 5 × 1 = 540 We NEED the remainders 10, 13, 16 and 25 ⇒ 12 - 10 = 2, 15 - 13 = 2, 18 - 16 = 2, 27 - 25 = 2 ∴ Difference is 2 in each case ⇒ We need to subtract 2 to from the LCM of 12, 15, 18, 27 = 540 - 2 = 538 ∴ Least number = 538 |
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