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Find the least number which when divided by 6, 15 and 18 leave remainder 5 in ee. |
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Answer» To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. L.C.M. of 6, 5 and 186 = 2*315 = 3*518 = 2*3*3 L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90 Now,5 + 90 = 95 Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case. |
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