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Find the length of a conductor which is moving with a velocity 0.4m/s in a magnetic field of 8T, inducing an emf of 20V if magnetic field, velocity and length of conductor are mutually perpendicular to each other.(a) 50m(b) 5m(c) 6.25m(d) 0.5mI had been asked this question in examination.I need to ask this question from Electromagnetic Induction topic in chapter Electromagnetism of Basic Electrical Engineering

Answer»

The correct answer is (c) 6.25m

The best I can explain: The formula for INDUCED EMF is: emf=Blv if B, l, v are PERPENDICULAR to each other. SUBSTITUTING the values of B, emf and v from the question, we get l=6.25m.



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