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Find the length of a conductor which is moving with a velocity 0.4m/s in a magnetic field of 8T, inducing an emf of 20V if magnetic field, velocity and length of conductor are mutually perpendicular to each other.(a) 50m(b) 5m(c) 6.25m(d) 0.5m |
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Answer» The correct answer is (c) 6.25m The best I can explain: The formula for induced emf is: emf=Blv if B, l, v are perpendicular to each other. Substituting the values of B, emf and v from the question, we get l=6.25m. |
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