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Find the length of the chord of the circle x2 + y2 – 6x – 4y – 12 = 0 on the coordinate axes. |
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Answer» Given x2 + y2 – 6x – 4y – 12 = 0 C = (3, 2) C = -12 Length intercepted by x-axis \(2\sqrt{q^2 - c} \) = 2\(\sqrt{9 + 12}\)= 2√21 units Length intercepted by y-axis = \(2\sqrt{f^2 - c}\) = \(2\sqrt{4 + 12}\) = 2√16 = 8 units. |
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