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Find the length of the chord of the circle x2 + y2 – 6x + 15y – 16 = 0 intercepted by the x-axis. |
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Answer» Given x2 + y2 – 6x + 15y – 6 = 0 C = \((3, \frac{-15}{2})\) & c = -16 Length intercepted by x – axis = 2\(\sqrt{q^2 - c}\) \(= 2\sqrt{(3)^2 - (-16)}\) = 2\(\sqrt{9 + 16}\) = 2√25 = 10 ∴ Length = 10 units |
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