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Find the length of the perpendicular from the origin to the plane. \(\vec {r}\)= .(3\(\vec {i}\) + 4\(\vec {j}\) + 12\(\vec {k}\)) = 26. |
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Answer» Taking the equation of the plane in cartesian form we get, (x\(\vec {i}\) + y\(\vec {j}\) + j\(\vec {k}\)) ⋅ (3\(\vec {i}\) + 4\(\vec {j}\) + 12\(\vec {k}\)) = 26 i.e. 3x + 4y + 12z – 26 = 0 The length of the perpendicular from (0, 0, 0) to the above plane is \(\pm\frac{-26}{\sqrt {9 + 16 + 144}}\) = +26/13 = 2 units |
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