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Find the locus of a point which remains at adistance of 5 units from the point (2, 3) |
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Answer» Let the point be (h,k)According to question, Distance between (2,3) and (h,k) 5 = √(2-h)² + (3-k)² 25 = 4 - 4h + h² + 9 - 6k + k² h² + k² - 4h - 6k = 25 - 13 = 12 Now put h = x and k = y x² + y² - 4x - 6y -12 = 0 |
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