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Find the locus of the point of intersection of the perpendiculartangents of the curve `y^2+4y-6x-2=0`.A. `2x-1=0`B. `2x+3=0`C. `2y+3=0`D. `2x+5=0` |
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Answer» Correct Answer - D Given equation reduces to `Y^(2)=6x` where `x+1=X` and `y+2=Y` `implies` Locus is directrix |
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