1.

Find the locus of the point of intersection of the perpendiculartangents of the curve `y^2+4y-6x-2=0`.A. `2x-1=0`B. `2x+3=0`C. `2y+3=0`D. `2x+5=0`

Answer» Correct Answer - D
Given equation reduces to `Y^(2)=6x` where `x+1=X` and `y+2=Y`
`implies` Locus is directrix


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