find the magnitude of charge present in 2.4g Mg 2+

1.	find the magnitude of charge present in 2.4g Mg 2+
Answer» No of moles of Mg+2 ion = given weight/molar weight\xa0here,\xa0given weight\xa0= 2.4\xa0g\xa0molar weight = 24 g/mol\xa0No of moles of Mg+2 ion = 2.4/24\xa0= 0.1\xa0molwe can see that in one mole of Mg+2 ion , 0.1\xa0mole electrons occur\xa0so, in two moles of Mg+2 ions = 0.1×2 moles of electrons occur .now, no of electrons = no of mole of electrons× Avogadro\'s constant= 0.2 × 6.023 × 10²³ =\xa01.2046 × 10²³we also know,\xa0charge of one electron = 1.6× 10-19 Cso, charge by total electrons = 1.2046 × 10²³ × 1.6 × 10-19 C\xa0=\xa01.92736\xa0× 104 C

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